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Author: Seppo Nurmi, Järfälla, Sweden. | |||
2. Laplace Operator in Ultraspherical Coordinates
Generally for orthogonal coordinates the Laplace operator can be expressed:
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| (2.1) | |||
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Substituting in a few steps the actual scalar coefficients we get for n-dimensional spherical coordinates:
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| (2.2) | |||
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By using (1.19) and (1.20)
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| (2.3) | |||
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further
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| (2.3) | |||
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and get finally using (1.21) the Laplace operator in n dimensions:
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| (2.4) | |||
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What we need is to find out is all the h:as
in the Laplace operator (2.4). Let us denote the purely
angular part, the part that only depends on the angular coordinates:
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| (2.5) | |||
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Now we can write the Laplace-operator in n-dimensional spherical coordinates in the following form:
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| (2.6) | |||
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We define below a recursive angular differential operator. This
operator has the property that it only includes angular coordinates
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| (2.7) | ||
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| (2.8) | |||
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and from (1.16)
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| (2.9) | |||
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| (2.10) | ||
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| (2.11) | |||
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and from (1.15) | |||
| (2.12) | |||
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We have in effect defined two sets of recursive scalar coefficients: | |||
| (2.13) | ||
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| (2.14) | ||
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A couple of results, to be used below
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| (2.15) | |||
| (2.16) | |||
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Define an angular differential operator of m angular variables:
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| (2.17) | |||
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To get the recursive formula, rewrite the sum-expression in a few steps: | |||
| (2.18) | |||
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using the result (2.15) | |||
| (2.19) | |||
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| (2.20) | |||
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In the last term in (2.20) we can identify the angular operator, with dimensions one less than above | |||
| (2.21) | |||
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Using result (2.16) above for the recursive scalar coefficients, we finally come to the recursive formula for the angular differential operator: | |||
| (2.22) | |||
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We also know (from the two- or three-dimensional case) for the first angle coordinate (azimuth):
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| (2.22) | |||
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The total Lapalace operator for the n-dimensional case was, from formula (2.6) | |||
Example: Spherical Laplace Operator in 4 dimensions | |||
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